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NEW QUESTION: 1
HOTSPOT
Your network contains an Active Directory domain named contoso.com. The domain contains two servers named Server1 and Server2 that run Windows Server 2016.
Server1 has Microsoft System Center 2016 Virtual Machine Manager (VMM) installed. Server2 has IP Address Management (IPAM) installed.
You create a domain user named User1.
You need to integrate IPAM and VMM. VMM must use the account of User1 to manage IPAM. The solution must use the principle of least privilege.
What should you do on each server? To answer, select the appropriate options in the answer are a.

Answer:
Explanation:

On Server1: Create a Run As Account that uses User1.
On Server2: Add User1 to IPAM ASM Administrator Role.
https://technet.microsoft.com/en-us/library/dn783349(v=ws.11).aspx
https://technet.microsoft.com/en-us/library/jj878348(v=ws.11).aspx

NEW QUESTION: 2
データストアのタイプを適切なシナリオに一致させます。
回答するには、適切なデータストアタイプを左側の列から右側のシナリオにドラッグします。各データストアタイプは、1回使用することも、複数回使用することも、まったく使用しないこともできます。
注：正しい一致はそれぞれ1ポイントの価値があります。

Answer:
Explanation:

Reference:
https://docs.microsoft.com/en-us/azure/architecture/guide/technology-choices/data-store-overview

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <vector>
# include <set>
# include <deque>
# include <iostream>
# include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out<<val<<" ";
}
};
struct Sequence {
int start;
Sequence(int start):start(start){}
int operator()() {
return start++ ;
}
};
int main() {
vector<int> v1(5);
generate(v1.begin(), v1.end(), Sequence(1));
set<int> s1(v1.rbegin(), v1.rend());
deque<int> d1(s1.rbegin(), s1.rend());
reverse(v1.begin(),v1.end());
reverse(s1.begin(), s1.end());
reverse(d1.begin(), d1.end());
for_each(v1.begin(), v1.end(), Out<int>(cout) );
for_each(s1.begin(), s1.end(), Out<int>(cout) );
for_each(d1.begin(), d1.end(), Out<int>(cout) );cout<<endl;
return 0;
}
Program outputs:
A. compilation error
B. 5 4 3 2 1 1 2 3 4 5 1 2 3 4 5
C. no output
D. 1 2 3 4 5 5 4 3 2 1 1 2 3 4 5
E. 1 2 3 4 5 1 2 3 4 5 5 4 3 2 1
Answer: A