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NEW QUESTION: 1
DRAG DROP
You need to prepare for the migration of virtual machines across the Hyper-V hosts of Customer2.
Which three actions should you perform in sequence? To answer, move the appropriate actions from the list of
actions to the answer area and arrange them in the correct order.

Answer:
Explanation:

http://blogs.technet.com/b/keithmayer/archive/2013/03/12/speaking-iscsi-with-windows-server-2012-and-hyper-
v.aspx

NEW QUESTION: 2
An architect is helping an organization with the Physical Design of an NSX-T Data Center solution. This information was gathered during a workshop:
* Any proposed solution must provide low latency.
* Any proposed solution must provide high throughput.
* Customer is running stock trading applications.
Which two should the architect recommend to meethigh-performance workload requirements? (Choose two.)
A. Leverage KVM as the compute host.
B. Leverage ESX as the compute host.
C. Enable enhanced data path mode on the N-VDS.
D. Enable latency sensitivity mode on the N-VDS.
E. UseLACP for all uplink profiles.
Answer: C,D
Explanation:
Explanation
https://docs.vmware.com/en/VMware-NSX-T-Data-Center/2.3/com.vmware.nsxt.install.doc/GUID-F459E3E4-F

NEW QUESTION: 3

A. Option C
B. Option D
C. Option B
D. Option A
Answer: D

NEW QUESTION: 4
企業の本社が、新しいオフィスの場所で使用するクラスBサブネットの一部をオフィスに提供しました。
指定範囲：172.30.232.0/24
* 57デバイスの販売
* HR 23デバイス
* IT 12デバイス
* 32デバイスのファイナンス
*マーケティング9デバイス
インストラクション
各部門に対応するために必要な最小数のアドレスを（CIDR表記を使用して）割り当てます。
各部門に対応した後、グラフィックの質問に回答して、サブネットの未使用部分を特定します。
すべてのドロップダウンに入力する必要があります。
いつでもシミュレーションの初期状態に戻したい場合は、[すべてリセット]ボタンをクリックしてください。


Answer:
Explanation:

Explanation:
Sales network - /26 - This will provide up to 62 usable IP addresses (64-2 for subnet and broadcast IP) HR network - /27 - This will provide for up to 30usable IP's (32-2) IT - /28 - This will provide for up to 14 usable IP's (16-2) Finance - /26 - Note that a /27 is 32 IP addresses but 2 of those are reserved for the network and broadcast IP's and can't be used for hosts.
Marketing - /28
If we add up how many IP blocks are used that is 64+32+16+64+16=192.
A /24 contains 256 IP addresses, so 256-192=64.
So the last unused box should be a /26, which equates to 64 addresses