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NEW QUESTION: 1
ネットワークエンジニアがOSPFv2ネイバー隣接関係を設定しています。パラメータを左側から右側の必要なカテゴリにドラッグアンドドロップしてください。すべてのパラメーターが使用されるわけではありません

Answer:
Explanation:

NEW QUESTION: 2
Webアプリケーションは、Amazon Kinesisストリームして12時間を使用します。
Kenesisストリーム内のデータに対して開発者はどのようにしてRESTで暗号化を実行できるか？
A. Encrypt the data once it is at rest with a Lambda function
B. Use Amazon Kinesis Consumer Library
C. Enable server-side encryption in Kinesis Streams
D. Enable SSL connections to Kinesis
Answer: C

NEW QUESTION: 3
Excelの列から特定の値を持つ行を選択するための最良の方法は何ですか？
オプションは次のとおりです。
A. 範囲の読み取りアクティビティを使用してExcelファイルの内容を取得し、[メソッドの選択]を使用して目的の行を特定します
B. Excelの検索機能を使用する
C. 範囲の読み取りアクティビティを使用してExcelファイルの内容を取得し、ForEachアクティビティループを使用してデータを反復処理して識別します
Answer: A

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the top half of the students arranged by their average marks must be given a rank of 1 and the remaining students must be given a rank of 2. Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT StudentCode as Code,
RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT Id, Name, Marks,
DENSE_RANK() OVER (ORDER BY Marks DESC) AS Rank
FROM StudentMarks
G. SELECT StudentCode as Code,
DENSE_RANK() OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: A