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NEW QUESTION: 1
An engineer receives a service ticket because a user cannot log into Cisco Unified CM User Options. Where
can the engineer verify that the user account is active?
A. LDAP Directory
B. Route Plan Report
C. LDAP System Configuration
D. End User Configuration
E. LDAP Authentication
Answer: D

NEW QUESTION: 2
Refer to the exhibit.

Redistribution is enabled between the routing protocols, and nowPC2 PC3, and PC4 cannot reach PC1. What are the two solutions to fix the problem? (Choose two.)
A. Filter all routes except EIGRP routes when redistributing into OSPF in R3.
B. Filter RIP AND OSPF routes back into OSPF from EIGRP when redistributing into OSPF in R2
C. Filter RIP routes back into RIP when redistributing into RIP in R2
D. Filter OSPF routes into RIP FROM EIGRP when redistributing into RIP in R2.
E. Filter all routes except RIP routes when redistributing into EIGRP in R2.
Answer: C,D
Explanation:
Explanation
Even PC2 cannot reach PC1 so there is something wrong with RIP redistribution in R2. Because RIP has higher Administrative Distance (AD) value than OSPF and EIGRP so it will be looped when doing mutual redistribution.

NEW QUESTION: 3
You are developing an application for an online retailer. The company ships only to certain countries.
The application must:
* Store a list of country codes in an array
* Validate the country code of the shipping address against the countries array
* Include a Boolean value in the array that indicates whether or not you can ship to the country
* Display a list of countries that can be shipped to if the user inputs a code for a country that the retailer cannot ship to You need to develop the application to meet the requirements.
Which code segment or segments should you use? (To answer, drag the appropriate code segment or segments from the list of code segments to the correct location or locations in the work area. Each code segment may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.)

Answer:
Explanation:

Explanation

* !arr[ctry] is true when the array element is false.
* The for..in statement iterates over the enumerable properties of an object, in arbitrary order. For each distinct property, statements can be executed.
Incorrect:
Not:

Would work fine if var i; would be replaced by i=0;
Reference: JavaScript Arrays; The for..in statement