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NEW QUESTION: 1
ボブは、EC2サービスにアクセスできるIAMユーザーです。 Adminは、IAMを含むすべてのAWSサービスにアクセスできるIAMユーザーです。ボブは自分のパスワードを変更できますか？
A. はい、AWSコンソールからのみ
B. はい、管理者が自分のパスワードを変更するためのBobアクセスをボブに付与した場合
C. いいえ、IAMユーザーはパスワードを変更できません
D. はい、AWS CLIからのみ
Answer: B
Explanation:
デフォルトでは、IAMユーザーは自分のパスワードを変更できません。ルート所有者またはIAM管理者は、パスワードポリシーページでポリシーを設定する必要があります。これにより、ユーザーは自分のパスワードを変更できます。有効にすると、IAMユーザーはいつでもAWSコンソールまたはCLIから自分のパスワードを変更できます。
参照：
http://docs.aws.amazon.com/IAM/latest/UserGuide/Using_ManagingUserPwdSelf.html

NEW QUESTION: 2
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
G. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
H. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: B
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx

NEW QUESTION: 3

A. Option C
B. Option D
C. Option A
D. Option B
Answer: C