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NEW QUESTION: 1
Powerful Performance Presenters (PPP) is a performance attribution and evaluation firm for pension consulting firms and has recently been hired by Stober and Robertson to conduct a performance attribution analysis for TopTech. Tom Harrison and Wendy Powell are the principals for PPP. Although performance attribution has come under fire lately because of its shortcomings, Stober believes PPP provides a needed service to its clients. Robertson shares Stober's view of performance attribution analysis.
Stober and Robertson request that Harrison and Powell provide a discussion of performance measures.
During a conversation on complements to attribution analysis, Harrison notes the uses of the Treynor ratio.
He states that the Treynor ratio is appropriate only when the investor's portfolio is well diversified. Powell states that the Sharpe ratio and the Treynor ratio will typically yield the same performance rankings for a set of portfolios.
Stober requests that PPP do some performance attribution calculations on TopTech's managers. In order to facilitate the analysis, Stober provides the information in the following table:

Harrison states one of PPP's services is that it will determine if TopTech has chosen a valid benchmark.
Stoher volunteers that indeed his firm's benchmark possesses the properties of a valid benchmark and describes its composition. The benchmark has the following characteristics:
* It uses the top 10% of U.S. portfolio managers each year in each asset class as the benchmark for TopTech managers;
* TopTech is very careful to make sure that its managers are familiar with the securities in each benchmark asset class;
* The identities and weights of various securities in the TopTech benchmark are clearly defined.
During a presentation to Stober, Robertson, and other TopTech executives, Harrison and Powell describe how macro attribution analysis can decompose an entire fund's excess returns into various levels. In his introduction, Robertson delineates the six levels as net contributions, risk-free return, asset categories, benchmarks, investment managers, and allocations effects.
Robertson states that TopTech has performed impressively at the investment managers level tor three years in a row. Harrison and Powell then describe the levels in greater detail. Harrison describes the benchmark level as the difference between active managers' returns and their benchmark returns. Powell states that the investment managers' level reflects the returns to active management on the part of the fund's managers, weighted by the amount actually allocated to each manager.
At the request of Stober, Harrison and Powell explore alternatives to the benchmark TopTech is currently using for its small-cap value manager. After some investigation of the small-cap value manager's emphasis, Harrison and Powell derive four potential custom benchmarks and calculate two measures to evaluate the benchmarks: (1) the return to the manager's active management or A = portfolio return - benchmark return; and (2) the return to the manager's style or S = benchmark return - broad market return.
The following characteristics are presented below for each benchmark: (1) the beta between the benchmark and the small-cap value portfolio; (2) the tracking error (i.e., the standard deviation of A); (3) the turnover of the benchmark; and (4) the correlation between A and S.

Harrison and Powell evaluate the benchmarks based on the four measures.
Based on an overall attribution analysis, does TopTech demonstrate superior ability to select stocks?
A. No, the within-sector selection effect is -3.2%.
B. No, the within-sector selection effect is -4.5%.
C. Yes, the within-sector selection effect is 1.3%.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
The within-sector selection effect measures the manager's ability to select superior securities to represent each sector in the portfolio. It is the sum of the weight for each sector in the benchmark times the difference in that sector's return in the portfolio and in the benchmark.
Within sector selection effect = (0.60)(0.187 - 0.286) + 0.25(0.158 - 0.124) + (0.15) (0.125 - 0.0885) = -
0.0594 + 0.0085 + 0.0055 = -0.0454 = -4.54%.
In sum, in the financial and large cap sectors, the manager chose superior stocks, so they show superior ability there. The overall within-sector selection effect is negative (-4.54%), however, so they do not show a consistent overall ability to select stocks.
The remaining component of attribution analysis (the allocation/selection interaction effect) can be calculated as the difference between the portfolio and benchmark weights for each sector multiplied by the difference between the return for the sector in the portfolio and the return for the sector in the benchmark.
The total allocation/ selection interaction effect is the sum of these products.
Allocation/selection interaction effect = (0.50 - 0.60)(0.187 - 0.286) + (0.30 - 0.25) (0.158 - 0.124) + (0.20 -
0.15)(0.125 - 0.0885) = 0.0099 + 0.0017 + 0.0018 = 0.0134= 1.34%.
The total excess return for the manager is then -1.80% + 1.34% - 4.54% = -5-00%.
This should be equal to the excess return calculated using the total returns for the benchmark and the portfolio. The total return for the benchmark is calculated above as 21.6%. For the portfolio it is: = (0.5) (0.187) + (0.3)(0.158) + (0.2)(0.125) = 16.6%. Thus the excess return calculated using the total returns for the portfolio and the benchmark is 16.6% - 21.6% = -5.0%. (Study Session 17, LOS 47.1)

NEW QUESTION: 2
Sie haben eine Berichtsanwendung, die eine Tabelle mit dem Namen Table1 verwendet. Sie stellen einen neuen Stapelaktualisierungsprozess bereit, um Aktualisierungen für Table1 durchzuführen.
Die Umgebung ist mit den folgenden Eigenschaften konfiguriert:
* Die Datenbank ist mit der Standardisolationseinstellung konfiguriert.
* Die Anwendung und der Prozess verwenden die Standardtransaktionsbehandlung.
Sie stellen fest, dass die Anwendung nicht auf Zeilen zugreifen kann, die vom Prozess verwendet werden.
Sie haben folgende Anforderungen:
* Stellen Sie sicher, dass die Anwendung nicht durch den Prozess blockiert wird.
* Stellen Sie sicher, dass die Anwendung eine konsistente Sicht auf die Daten hat
* Stellen Sie sicher, dass die Anwendung keine schmutzigen Daten liest.
Sie müssen das Problem beheben und die Anforderungen mit dem geringsten Verwaltungsaufwand erfüllen.
Was tun?
A. Aktivieren Sie die Datenbank für die Isolationsstufe READ_COMITTED_SNAPSHOT.
B. Aktivieren Sie die Anwendung für den WITH (NOLOCK) -Hinweis.
C. Aktivieren Sie die Datenbank für die Isolationsstufe ALLOW_SNAPSHOT_ISOLATION. Ändern Sie die Anwendung und den Aktualisierungsprozess für die SNAPSHOT-Isolationsstufe.
D. Aktivieren Sie die Datenbank für die Isolationsstufe ALLOW_SNAPSHOT_ISOLATION. Ändern Sie die Anwendung für die Isolationsstufe SERIALIZABLE.
Answer: A
Explanation:
Explanation
Snapshot isolation must be enabled by setting the ALLOW_SNAPSHOT_ISOLATION ON database option before it is used in transactions. This activates the mechanism for storing row versions in the temporary database (tempdb).
READ COMMITTED is the default isolation level for SQL Server. It prevents dirty reads by specifying that statements cannot read data values that have been modified but not yet committed by other transactions. Other transactions can still modify, insert, or delete data between executions of individual statements within the current transaction, resulting in non-repeatable reads, or "phantom" data.

NEW QUESTION: 3
Which changes introduced independently will allow code to compile and display 0 1 8 9
(choose all that apply)
#include <iostream>
# include <set>
# include <vector>
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
A t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<A>v(t, t+10);
set<A> s1(v.begin(),v.end());
s1.insert(v.begin(),v.end());
s1.erase(s1.lower_bound(2),s1.upper_bound(7));
for(set<A>::iterator i=s1.begin();i!= s1.end(); i++) {
cout<<i?>getA()<<" ";
}
cout<<endl;
return 0;
}
A. operator int() const { return a;} inserted at Place 1
B. bool operator < (const A & a, const A & b) { return a.getA()<b.getA();} inserted at Place 2
C. bool operator < (const A & b) const { return b.a<a;} inserted at Place 1
D. bool operator < (const A & b) const { return a<b.a;} inserted at Place 1
Answer: A,B,D