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NEW QUESTION: 1
귀하는 많은 웹 서비스를 제공하는 SaaS 회사의 개발자입니다.
회사의 모든 웹 서비스는 다음 요구 사항을 충족해야 합니다.
* API 관리를 사용하여 서비스에 액세스하십시오.
* 인증을 위해 OpenID Connect를 사용하십시오.
* 익명의 사용 금지
최근 보안 감사에서는 인증없이 여러 웹 서비스를 호출 할 수 있음을 발견했습니다.
어떤 API 관리 정책을 구현해야 합니까?
A. jsonp
B. validate-jwt
C. 인증 인증서
D. 체크 헤더
Answer: B
Explanation:
Add the validate-jwt policy to validate the OAuth token for every incoming request.
Incorrect Answers:
B: The jsonp policy adds JSON with padding (JSONP) support to an operation or an API to allow cross-domain calls from JavaScript browser-based clients. JSONP is a method used in JavaScript programs to request data from a server in a different domain. JSONP bypasses the limitation enforced by most web browsers where access to web pages must be in the same domain.
JSONP - Adds JSON with padding (JSONP) support to an operation or an API to allow cross-domain calls from JavaScript browser-based clients.
References:https://docs.microsoft.com/en-us/azure/api-management/api-management-howto-protect-backend-with-aad

NEW QUESTION: 2

A. Option A
B. Option C
C. Option D
D. Option B
Answer: C

NEW QUESTION: 3
DRAG DROP
Drag and drop the CSMA components from the left onto the correct descriptions on the right

Answer:
Explanation:
Access mode used for Ethernet networks = 1-Persistent
Access mode used for Wi-fi networks = P-Persistent
Access mode used in the controller area network = O-persistent
Rules that define the system response when a collision occurs on an Ethernet network = CSMA/CD Rules that define the system response when a collision occurs on a Wi-Fi network = CSMA/CA

NEW QUESTION: 4
文字「e」を含み、最後から2番目の位置に文字「a」を持つ、CUSTOMERSテーブルのすべての顧客の名を表示する必要があります。
どのクエリで必要な出力が得られますか？
A. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')IS NOT NULL ANDSUBSTR(cust_first_name, 1, -2)='a';
B. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR(cust_first_name, LENGTH(cust_first_name), -2)='a';
C. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>0 ANDSUBSTR(cust_first_name, -2, 1)='a';
D. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, 'e')<>'' ANDSUBSTR(cust_first_name, -2, 1)='a';
Answer: C