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NEW QUESTION: 1
A network administrator is building two IRF domains:
-One domain for the two distribution layer switches -One domain for the access layer switches
Each access layer switch should have a connection to each distribution layer switch. In this design, how many access switches can the administrator have in the access layer IRF domain before spanning tree is required to remove loops between the two IRF domains?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: A

NEW QUESTION: 2
ネイティブVLANはネットワークでどのように保護されていますか？
A. 管理ドメイン内の他のVLANから分離
B. プライベートVLAN範囲の値を指定します
C. VLAN1として割り当てます
D. リンクの両端で異なるVLANIDとして構成します
Answer: D

NEW QUESTION: 3
Which statements are true about EIGRP successor routes? (Choose two.)
A. Successor routes are saved in the topology table to be used if the primary route fails.
B. A successor route may be backed up by a feasible successor route.
C. Successor routes are flagged as 'active' in the routing table.
D. Successor routes are stored in the neighbor table following the discovery process.
E. A successor route is used by EIGRP to forward traffic to a destination.
Answer: B,E
Explanation:
Introduction to EIGRP
http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080093f07.shtml
Explanation:
Feasible Successors
A destination entry is moved from the topology table to the routing table when there is a feasible successor. All
minimum cost paths to the destination form a set. From this set, the neighbors that have an advertised metric less
than the current routing table metric are considered feasible successors.
Feasible successors are viewed by a router as neighbors that are downstream with respect to the destination.
These neighbors and the associated metrics are placed in the forwarding table.
When a neighbor changes the metric it has been advertising or a topology change occurs in the network, the set of
feasible successors may have to be re-evaluated. However, this is not categorized as a route recomputation.

NEW QUESTION: 4
How is the time that an agent waits for log records to be flushed to disk calculated?
A. LOG_WRITE_TIME divided by TOTAL_COMMITS
B. LOG_END_TIME divided by TOTAL_COMMITS
C. LOG_WAIT_TIME divided by TOTAL_COMMITS
D. LOG_FLUSH_TIME divided by TOTAL_COMMITS
Answer: A