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NEW QUESTION: 1
DRAG DROP
Drag and drop the BGP states from the left to the matching definitions on the right.

Answer:
Explanation:

NEW QUESTION: 2
HOTSPOT
You are planning the deployment of two new Always On Failover Cluster Instances (FCIs) of Microsoft SQL Server to a single Windows Server Cluster with three nodes. The planned configuration for the cluster is shown in the Server Layout exhibit. (Click the Exhibit button.)

The SAN team has configured storage for the cluster and sent the configuration to you in the email shown in the SAN Team Email exhibit. (Click the Exhibit button.)

Each node of the cluster has identical local storage available as shown in the Local Storage exhibit. (Click the Exhibit button.)

All local storage is on SSD.
You need to plan specific configurations for the new cluster.
For each of the following statement, select Yes if the statement is true. Otherwise, select No.

Answer:
Explanation:

Box 1: Yes
tempdb on local storage. FCIs now support placement of tempdb on local non-shared storage, such as a local solid-state-drive, potentially offloading a significant amount of I/O from a shared SAN.
Prior to SQL Server 2012, FCIs required tempdb to be located on a symmetrical shared storage volume that failed over with other system databases.
Box 2: No
The VNN is set on the group level, not on the instance level.
Database client applications can connect directly to a SQL Server instance network name, or they may connect to a virtual network name (VNN) that is bound to an availability group listener. The VNN abstracts the WSFC cluster and availability group topology, logically redirecting connection requests to the appropriate SQL Server instance and database replica.
The logical topology of a representative AlwaysOn solution is illustrated in this diagram:

References: http://download.microsoft.com/download/d/2/0/d20e1c5f-72ea-4505-9f26- fef9550efd44/microsoft%20sql%20server%20alwayson%20solutions%20guide%20for%20high%20availa bility%20and%20disaster%20recovery.docx

NEW QUESTION: 3
Examine the structure of the EMPLOYEEStable.

There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?
A. SELECT e.last_name, e.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
B. SELECT e.last_name, m.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123;
C. SELECT e.last_name, m.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123;
D. SELECT m.last_name, e.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123;
Answer: D