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NEW QUESTION: 1
A service had an inbound SOAP/HTTP binding. There is no external load balancer available. The Invocation overhead under extremely high load volumes causes requests to queue for dispatch. What is the recommended way to improve request dispatch concurrency?
Options are :
A. change from a SOAP binding to a virtualization binding
B. use policies to specify the thread pool management
C. deploy additional service instance to handle the request load
D. implement a flow-control policy set to limit the rate if incoming requests
Answer: B

NEW QUESTION: 2
Given a file containing ordered number, i.e. "123456789," match each of the following redundant Array of independent Disks (RAID) levels to the corresponding visual representation visual representation. Note: P() = parity.
Drag each level to the appropriate place on the diagram.

Answer:
Explanation:
Explanation

NEW QUESTION: 3
Which attribute is used in authentication in a Microsoft Active Directory LDAP authentication realm?
A. cn
B. sAMAccountName
C. last name
D. firstname
Answer: A

NEW QUESTION: 4
Refer to the exhibit. The network is converged.
After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?

A. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via
190.172.23.10, 00:00:16, Serial 1/0
B. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via
190.173.23.10, 00:00:16, FastEthernet 0/0
C. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0 O 208.149.23.96 [110/13] via
190.173.23.10, 00:00:16, FastEthernet 0/0
D. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/13] via
190.172.23.10, 00:00:16, Serial 1/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets -B is not correct. The cost through T1 link is much higher than through T3 link (T1 cost
108 / 1.544 Mbps = 64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -
> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 -C & D are not correct.
In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -they are surely incorrect.